## PrepTest 73, Game 4, Question 21

### Transcript

Question 21 is another local question, although this time the local condition is added to a partial solution question. They want a complete and accurate list of things that could be in bouquet two at the same time. So we're going to start with the if condition, put down some spaces to add it to and then put the T in place.

Now of course, because of the last rule anytime you have a T, you have to add a P. And because of the first rule, anytime something goes into bouquet one, it isn't allowed into bouquet three. So bouquet three is gonna lose L, P, and T. Now remember that bouquet three does need to have two things it shares with bouquet two.

And since we've struck three things, that means that the only two that are left S and R are going to have to be what fills out the bouquet three. Which means that bouquet one is not going to be able to get those flowers. It can't have an R or an S. And also it can't have the L because if you don't get an R, you also can't have an L.

And then of course, bouquet two is going to get the two flowers that bouquet three has definitely. It'll get an S and an R. Now at this point bouquets one and three are filled. Each of them has two things and then they've gotten rid of three things. So only bouquet two is open for new things.

Because bouquet two has an S, then we know it can't have an L but whether it has a P and a T is open, it could have a T and a P both or it could just have a P. Remember, you can have P without T, even if you can't have T without P. That's as far as we're going to be able to take the sketch. But now notice we do know something about bouquet two. It has to have both S and R in it.

So if you look at the answer choices, we can go ahead and eliminate answer choices A and D because they don't have an S. And we can eliminate answer choices B and C because they don't have an R. Which means the only answer it could be is answer choice E. It could be that we have the S and the R and then both a P and a T. So E is our answer and we move to the next question.

Read full transcriptNow of course, because of the last rule anytime you have a T, you have to add a P. And because of the first rule, anytime something goes into bouquet one, it isn't allowed into bouquet three. So bouquet three is gonna lose L, P, and T. Now remember that bouquet three does need to have two things it shares with bouquet two.

And since we've struck three things, that means that the only two that are left S and R are going to have to be what fills out the bouquet three. Which means that bouquet one is not going to be able to get those flowers. It can't have an R or an S. And also it can't have the L because if you don't get an R, you also can't have an L.

And then of course, bouquet two is going to get the two flowers that bouquet three has definitely. It'll get an S and an R. Now at this point bouquets one and three are filled. Each of them has two things and then they've gotten rid of three things. So only bouquet two is open for new things.

Because bouquet two has an S, then we know it can't have an L but whether it has a P and a T is open, it could have a T and a P both or it could just have a P. Remember, you can have P without T, even if you can't have T without P. That's as far as we're going to be able to take the sketch. But now notice we do know something about bouquet two. It has to have both S and R in it.

So if you look at the answer choices, we can go ahead and eliminate answer choices A and D because they don't have an S. And we can eliminate answer choices B and C because they don't have an R. Which means the only answer it could be is answer choice E. It could be that we have the S and the R and then both a P and a T. So E is our answer and we move to the next question.